A fixed mass of gas of volume 600cm3 at a temperature of 27oC is cooled at constant pressure to a temperature of 0oC. What is the change in volume?
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Correct Answer: Option A
Explanation:
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
T2 = 0 + 273 = 273k
V1 = 600
T1 = 27 + 273 = 300k
V2 = \(\frac{V_1T_2}{T_1}\) = 546cm
V1 - V2 = 54cm
\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)
T2 = 0 + 273 = 273k
V1 = 600
T1 = 27 + 273 = 300k
V2 = \(\frac{V_1T_2}{T_1}\) = 546cm
V1 - V2 = 54cm