An electron charge 1.6 x 10-19C is accelerated in vacuum from rest at zero volt towards a plate at 40k V. Calculate the kinetic energy of the electron
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Correct Answer: Option D
Explanation:
E = \(\frac{1}{2}QV = \frac{1}{2} \times 1.6 \times 10^{-19} \times 40000\)
= 3.2 x 10-15J
E = \(\frac{1}{2}QV = \frac{1}{2} \times 1.6 \times 10^{-19} \times 40000\)
= 3.2 x 10-15J