The work function of a metal is 4.65ev and the metal is illuminated with a radiation of 6.86ev. What is the kinetic energy of the electrons ejected from the surface of the metal?
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Correct Answer: Option B
Explanation:
K.E = \(\frac{1}{2}\)mv2
E - W = 6.86 - 4.65
= 2.21ev
K.E = \(\frac{1}{2}\)mv2
E - W = 6.86 - 4.65
= 2.21ev