A body of mass 5kg falls from a height of 10m above the ground. What is the kinetic energy of the body just before it strikes the ground? (Neglect energy losses and take gas 10ms2)
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Correct Answer: Option D
Explanation:
v2 = u2 + 2gh = 0 + 2 x 10 x 10
v2 = 200; K.E = 1/2mv2 = 1/2 x 5 x 200 = 500J
v2 = u2 + 2gh = 0 + 2 x 10 x 10
v2 = 200; K.E = 1/2mv2 = 1/2 x 5 x 200 = 500J