The diagram above shows a waveform in which energy is transferred from A to B in a time of 2.5 x 10-3s. Calculate the frequency of the wave
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Correct Answer: Option B
Explanation:
The waveform moved from A to B in \(2.5 \times 10^{-3}\) seconds.
From the diagram, A to B has \(2\frac{1}{2}\) complete oscillations between it, Therefore, the period of the oscillation is
\(\frac{2.5 \times 10^{-3}}{2.5} = 1 \times 10^{-3} s\)
\(Frequency = \frac{1}{Period}\)
= \(\frac{1}{1 \times 10^{-3}} = 1 \times 10^{3} Hz\)
The waveform moved from A to B in \(2.5 \times 10^{-3}\) seconds.
From the diagram, A to B has \(2\frac{1}{2}\) complete oscillations between it, Therefore, the period of the oscillation is
\(\frac{2.5 \times 10^{-3}}{2.5} = 1 \times 10^{-3} s\)
\(Frequency = \frac{1}{Period}\)
= \(\frac{1}{1 \times 10^{-3}} = 1 \times 10^{3} Hz\)