Calculate the energy stored in 20μF capacitor if the potential difference between the plates is 40 V.
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Correct Answer: Option B
Explanation:
E = 1/2cv2 = 1/2 x 10 x 10-6 x 402 = 1.6 x 10-2J
E = 1/2cv2 = 1/2 x 10 x 10-6 x 402 = 1.6 x 10-2J