A man stands in front of a tall wall and produces a sound. If he receives the echo of the sound two seconds later, calculate his distance from the wall. (The speed of sound in air is 330ms-1)
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Correct Answer: Option C
Explanation:
x = vt/2 = \(\frac {330 \times 2} {2}\) = 660/2 = 330m
x = vt/2 = \(\frac {330 \times 2} {2}\) = 660/2 = 330m