A battery of e.m.f 10V an internal resistance 2Ω is connected to a resistance of 6Ω. Calculate the p.d
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Correct Answer: Option B
Explanation:
V = E - Ir = 10V - \(\frac{10 \times 2}{8}\) = 7.5V
V = E - Ir = 10V - \(\frac{10 \times 2}{8}\) = 7.5V