An electric kettle rated 1500W boils away 0.3kg of a liquid at its boiling point every 300s. Calculate the specific latent heat of the vaporisation of the liquid
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Correct Answer: Option A
Explanation:
Pt=mI; I=\(\frac{1500\times300}{0.3}=1.5\times10^6Jkg^-1\)
Pt=mI; I=\(\frac{1500\times300}{0.3}=1.5\times10^6Jkg^-1\)