A rocket is launched from the surface of the earth. If the radius of the earth is 6.4 x 106m and the acceleration of free fall due to gravity is 1Oms-1 calculate the escape velocity of the rocket.
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Correct Answer: Option B
Explanation:
V = √2gR
V = √2 x 10 x 6.4 x 102
1.13 x 104ms
V = √2gR
V = √2 x 10 x 6.4 x 102
1.13 x 104ms