A platinum-resistance thermometer has a resistance of 5Ω at 0°C and 9Ω at l00°C. Assuming that resistance changes uniformly with temperature, calculate the resistance of the thermometer when the temperature is 45°C.
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Correct Answer: Option C
Explanation:
\(\frac{\theta}{100} = \frac{R_ {\theta} - R_0}{R_{100} - R_0}\)
\(\frac{45}{100} = \frac{R_{\theta} - 5}{9 - 5}\)
\(45 \times 4 = 100(R_{\theta} - 5)\)
\(180 = 100R_{\theta} - 500\)
\(180 + 500 = 100R_{\theta}\)
\(R_{\theta} = \frac{680}{100}\)
\(R_{\theta} = 6.8 \Omega\)
\(\frac{\theta}{100} = \frac{R_ {\theta} - R_0}{R_{100} - R_0}\)
\(\frac{45}{100} = \frac{R_{\theta} - 5}{9 - 5}\)
\(45 \times 4 = 100(R_{\theta} - 5)\)
\(180 = 100R_{\theta} - 500\)
\(180 + 500 = 100R_{\theta}\)
\(R_{\theta} = \frac{680}{100}\)
\(R_{\theta} = 6.8 \Omega\)