The current in the primary coil of a transformer is 2.5A. If the coil has 50 turns and the secondary250 turns, calculate the current in the secondary coil. Neglect energy losses in the transformer
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Correct Answer: Option B
Explanation:
\(\frac{I_s}{I_p}=\frac{n_p}{n_s}, I_s= \frac{I_pn_p}{n_s}=\frac{2.5\times50}{250}\Rightarrow0.5A\)
\(\frac{I_s}{I_p}=\frac{n_p}{n_s}, I_s= \frac{I_pn_p}{n_s}=\frac{2.5\times50}{250}\Rightarrow0.5A\)