A progressive wave has a wavelength of 50cm. calculate the phase difference between two points at a distance of 20cm apart.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
Phase difference = \(\frac{2\pi x}{\lambda}\)
= \(\frac{2\pi \times 20}{50}\)
= \(\frac{4}{5} \pi\)
Phase difference = \(\frac{2\pi x}{\lambda}\)
= \(\frac{2\pi \times 20}{50}\)
= \(\frac{4}{5} \pi\)