A capacitor of capacitance 25µF is connected to an a.c power source of frequency 200/πHz. Calculate the reactance of the capacitor
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Correct Answer: Option D
Explanation:
\(X_c=\frac{1}{2\pi{fc}}\)=\(\frac{1}{2\times\pi\times\frac{200}{\pi}\times 25\times 10^{-6}}=\frac{10^6}{10^4}\)=100 Ω
\(X_c=\frac{1}{2\pi{fc}}\)=\(\frac{1}{2\times\pi\times\frac{200}{\pi}\times 25\times 10^{-6}}=\frac{10^6}{10^4}\)=100 Ω