A rectangular block of wood floats in water with two-thirds of its volume immersed. When placed in another liquid, it floats with half of its volume immersed. Calculate the relative density of the liquid
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Correct Answer: Option E
Explanation:
R.D = \(\frac{\text{volume of liquid displaced}}{\text{volume of water displaced}}\)
= \(\frac{1}{2} - \frac{2}{3} = \frac{1}{2} \times \frac{3}{2} = \frac{3}{4}\)
= 0.75
R.D = \(\frac{\text{volume of liquid displaced}}{\text{volume of water displaced}}\)
= \(\frac{1}{2} - \frac{2}{3} = \frac{1}{2} \times \frac{3}{2} = \frac{3}{4}\)
= 0.75