A piece of brass of mass 170kg has its temperature raised from 0oC to 30oC. Calculate its increase in volume, given the density of brass at 0oC as 8.5 x 103kgm3 and its cubic expansivity as 5.7 x 10-1k1
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Correct Answer: Option C
Explanation:
V = \(\frac{m}{p}= \frac{170}{8.5 x 10^{-3}}\) = 0.02
= \(\Delta\)\(\frac{\delta V}{V \delta T}\)
\(\delta V\) = \(\Delta\) x V x \(\delta\)T
= 5.7 x 10-5 x 0,02 x 30
= 0 3.42 x 10-5
V = \(\frac{m}{p}= \frac{170}{8.5 x 10^{-3}}\) = 0.02
= \(\Delta\)\(\frac{\delta V}{V \delta T}\)
\(\delta V\) = \(\Delta\) x V x \(\delta\)T
= 5.7 x 10-5 x 0,02 x 30
= 0 3.42 x 10-5