A cell of e.m.f. 1.5v is connected in series with a resistor of 3\(\Omega\). A high resistance voltmeter connected across the cell registers only 0.9v. Calculate the internal resistance of the cell
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Correct Answer: Option A
Explanation:
I = \(\frac{V}{R} = \frac{0.9}{3} = 3\)
r = \(\frac{E}{I} = \frac{1.5}{0.3} = 5\)
I = \(\frac{V}{R} = \frac{0.9}{3} = 3\)
r = \(\frac{E}{I} = \frac{1.5}{0.3} = 5\)