Use the following data to determine the length L of a wire when a fore of 30N is applied, assuming Hooke's law is obeyed
\(\begin{array}{c|c}\text{Force applied/N} & 0 & 5 & 10 & 30\\ \hline \text{length of wire/mm} & 500.0 & 500.0 & 501.0 & L \end{array}\)
\(\begin{array}{c|c}\text{Force applied/N} & 0 & 5 & 10 & 30\\ \hline \text{length of wire/mm} & 500.0 & 500.0 & 501.0 & L \end{array}\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
F \(\alpha\) e
F = ke
K = \(\frac{F}{e} = \frac{5}{0.5} = 10\)
when F = 30, e = \(\frac{F}{K} = \frac{30}{10} = 3\)
L = 500 + 3 = 503.00
F \(\alpha\) e
F = ke
K = \(\frac{F}{e} = \frac{5}{0.5} = 10\)
when F = 30, e = \(\frac{F}{K} = \frac{30}{10} = 3\)
L = 500 + 3 = 503.00