A stone is projected horizontally from the top of a tower with a speed of 5ms-1. It lands on the ground level at a horizontal distance of 20m from the foot of the tower. Calculate the height of the tower. (g = 10ms\(^{-2}\))
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option n
Explanation:
H = \(\frac{1}{2} gt^2\) S = ut
t = \(\frac{5}{u} = \frac{20}{5} = 45\)
H = \(\frac{1}{2}gt^2 = \frac{1}{2} \times 10 x 4^2\)
= 80m
H = \(\frac{1}{2} gt^2\) S = ut
t = \(\frac{5}{u} = \frac{20}{5} = 45\)
H = \(\frac{1}{2}gt^2 = \frac{1}{2} \times 10 x 4^2\)
= 80m