In the diagram given, the current passing through the 6\(\Omega\) resistor is 1.5A. Calculate the terminal p.d. of the battery in the diagram
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Correct Answer: Option C
Explanation:
C.V = 1R1 + 1R2/sub>
= (1.2 1.5) + (1.5 6)
= 1.8 + 9
= 10.80V
C.V = 1R1 + 1R2/sub>
= (1.2 1.5) + (1.5 6)
= 1.8 + 9
= 10.80V