If the frequency of the tuning fork at resonance is 256Hz, calculate the frequency of vibration of the wire when the tension in he wire is increased to 196N
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Correct Answer: Option C
Explanation:
\(\frac{f}{256} = \sqrt{\frac{196}{100}}\)
f = \(\sqrt{\frac{256^2 \times 196}{100}}\)
= 356.4Hz
\(\frac{f}{256} = \sqrt{\frac{196}{100}}\)
f = \(\sqrt{\frac{256^2 \times 196}{100}}\)
= 356.4Hz