(a) The mass and wavelength of a moving electron are 9.0 x 10\(^{-31}\) kg and 1.0 x 10\(^{-10}\)m respectively. Calculate the kinetic energy of the electron. [ h = 6.6 x 10\(^{-34}\) Js]
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Correct Answer: Option n
Explanation:
\(\lambda = \frac{h}{p} = \frac{h}{mv}\)
V = \(\frac{h}{m_2}\)
Electron kitenic energy = \(\frac{1}{2} MV^2 = \frac{h^2}{2m \lambda^2}\)
= \(\frac{(6.6 \times 10^{-34})^2}{2 \times 9.0 \times 10^{-37} \times 1.0 \times 10^{-20}}\) = 2.39 x 10\(^{-17}\)J
\(\lambda = \frac{h}{p} = \frac{h}{mv}\)
V = \(\frac{h}{m_2}\)
Electron kitenic energy = \(\frac{1}{2} MV^2 = \frac{h^2}{2m \lambda^2}\)
= \(\frac{(6.6 \times 10^{-34})^2}{2 \times 9.0 \times 10^{-37} \times 1.0 \times 10^{-20}}\) = 2.39 x 10\(^{-17}\)J