A reservoir is filled with a liquid of density 2000kgm-3. Calculate the depth at which the pressure in the liquid will equal to 9100Nm-2 [g = 10ms-2]
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Correct Answer: Option B
Explanation:
h = \(\frac{p}{eg} = \frac{9100}{2000 \times 10} = 0.455m\)
h = \(\frac{p}{eg} = \frac{9100}{2000 \times 10} = 0.455m\)