A boy travels 8 km eastward to a point B and then 6km northward to another point C. Determine the difference between the magnitude of displacement of the boy and distance travelled by him
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:

AC = \(\sqrt{8^2 + 6^2}\) = 10km
Distance travelled = 8 + 6 = 14km
Difference = 4 - 10 = 4km
AC = \(\sqrt{8^2 + 6^2}\) = 10km
Distance travelled = 8 + 6 = 14km
Difference = 4 - 10 = 4km