A spiral spring of natural length 30.0cm and force constant of 20Nm-1 is compressed to 20.0cm. Calculate the energy stored in the spring
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Correct Answer: Option A
Explanation:
Energy = \(\frac{1}{2} ke^2 = \frac{1}{2} \times 20 \times 0.1^2\)
= 0.1J
Energy = \(\frac{1}{2} ke^2 = \frac{1}{2} \times 20 \times 0.1^2\)
= 0.1J