A piece of metal of relative density 5.0 weighs 60N in air. Calculate its weight when fully immersed in water
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Correct Answer: Option C
Explanation:
R.D = \(\frac{m}{m - m_2} = 5 = \frac{6}{60 - m_1} = \frac{240}{5} = 48N\)
R.D = \(\frac{m}{m - m_2} = 5 = \frac{6}{60 - m_1} = \frac{240}{5} = 48N\)