The volume of a given mass of an ideal gas at 327k and 9.52 x 104 Pa is 40cm3. calculate the volume of the gas at 273k and 1.034 x 105Pa.
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Correct Answer: Option D
Explanation:
\(V_2 = \frac{P_1V_1T_2}{P_2T_1} = \frac{9.52 \times 10^4 \times 40 \times 273}{1.034 \times 10^5 \times 327}\)
= 30.75cm3
\(V_2 = \frac{P_1V_1T_2}{P_2T_1} = \frac{9.52 \times 10^4 \times 40 \times 273}{1.034 \times 10^5 \times 327}\)
= 30.75cm3