The horizontal floor of a water reservoir appears to be 1.0m deep when viewed vertically from above. If the refractive index of water is 1.35, calculate the real depth of the reservoir
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Correct Answer: Option B
Explanation:
n = \(\frac{R.d}{A.d}\)
1.35 = \(\frac{R.d}{1}\)
R.d = 1.35m
n = \(\frac{R.d}{A.d}\)
1.35 = \(\frac{R.d}{1}\)
R.d = 1.35m