Calculate the change in volume when 90g of ice is completely melted. [density of water = 1g cm-3, density of ice = 0.9cm-3]
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Correct Answer: Option C
Explanation:
\(\Delta\)y = Vice - Vwater
= \(\frac{90}{0.9} - \frac{90}{1} = 10cm^3\)
\(\Delta\)y = Vice - Vwater
= \(\frac{90}{0.9} - \frac{90}{1} = 10cm^3\)