A ball bearing is projected vertically upwards from the ground with a velocity of 15ms-1. Calculate the time taken by the ball to return to the ground [g = 10ms-1]
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Correct Answer: Option B
Explanation:
t = 2\(\frac{(v - u)}{g} = 2\frac{(0 - 15)}{-10}\)
\(\frac{2 \times 15}{10}\) = 3.0s
t = 2\(\frac{(v - u)}{g} = 2\frac{(0 - 15)}{-10}\)
\(\frac{2 \times 15}{10}\) = 3.0s