A Spiral spring of natural length 20.00cm has a scale hanging freely in its lower end. When an object ass 40 g is placed in the pan. its length becomes cm. When the object is replaced with another of 60g, the length becomes 22.05cm. Calculate the mass scale pan. [g = 10 ms\(^{-2}\)]
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Correct Answer: Option n
Explanation:
Mg = Ke ; (m + 40)g = 1.80k .................. (i)
(m + 60)g = 2.05K ................ (ii)
\(\frac{m + 40}{m + 60} = \frac{1.80}{2.05}\)
1.80 (m + 60) = 2.05 (m + 40)
m = \(\frac{26}{0.25} = 104g\)
Mg = Ke ; (m + 40)g = 1.80k .................. (i)
(m + 60)g = 2.05K ................ (ii)
\(\frac{m + 40}{m + 60} = \frac{1.80}{2.05}\)
1.80 (m + 60) = 2.05 (m + 40)
m = \(\frac{26}{0.25} = 104g\)