A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor
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Correct Answer: Option A
Explanation:
Q = CV
= 600 x 10-6 x 200 = 1.2C
Q = CV
= 600 x 10-6 x 200 = 1.2C