A constantan wire has a cross sectional area of 4 x 10-8m2 and a resistivity of 1.1 x 10-6\(\Omega\)m. If a resistor of resistance 11\(\Omega\) is to be made from this wire, calculate the length of the wire required
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Correct Answer: Option A
Explanation:
L = \(\frac{RA}{e} = \frac{11 \times 4 \times 10^{-8}}{1.1 \times 10{-4}} = 0.4m\)
L = \(\frac{RA}{e} = \frac{11 \times 4 \times 10^{-8}}{1.1 \times 10{-4}} = 0.4m\)