A quantity of steam at 100oC condenses to water at the same temperature by releasing 6.9 x 104J of energy. Calculate the mass of the condensed steam. [specific latent heat of vaporization of eater = 2.3 x 106 J kg-1]
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Correct Answer: Option B
Explanation:
M = \(\frac{Q}{T} = \frac{6.9 \times 10^{4}}{2.3 \times 10^6} = 3 \times 10^{-2} kg\)
M = \(\frac{Q}{T} = \frac{6.9 \times 10^{4}}{2.3 \times 10^6} = 3 \times 10^{-2} kg\)