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An atom \(^{234}_{91} P\) emits a gamma radiation. The resultant nuclide is

An atom \(^{234}_{91} P\) emits a gamma radiation. The resultant nuclide is
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  • A \(^{230}_{90} Th\)
  • B \(^{234}_{91} Pa\)
  • C \(^{234}_{90} Th\)
  • D \(^{234}_{89} Ac\)
Correct Answer: Option B
Explanation:

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