Determine the magnitude of P in the diagram above
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
X = 50 sin30 = 30 x 0.5 = 25cm
40 x 20 = p x 25
p = \(\frac{40 \times 20}{25}\)
= 32N
X = 50 sin30 = 30 x 0.5 = 25cm
40 x 20 = p x 25
p = \(\frac{40 \times 20}{25}\)
= 32N