(a) State two;
(i) laws of solid friction;
(ii) advantages of friction;
(iii) methods of reducing friction.
(b) Draw and label a diagram of a pulley system with velocity ratio of 5.
(c)(i) Show that the efficiency L, force ratio M.A. and the velocity ratio V.R. of a machine are related by the equation \(E = \frac{M.A.}{V.R}\) x 100%.
(ii) The efficiency of a machine is 80%. Calcuate the work done by a person using the machine to raise a load of 300 kg through a height of 4 m.[ g = 10 ms\(^{-2}\) ]
(i) laws of solid friction;
(ii) advantages of friction;
(iii) methods of reducing friction.
(b) Draw and label a diagram of a pulley system with velocity ratio of 5.
(c)(i) Show that the efficiency L, force ratio M.A. and the velocity ratio V.R. of a machine are related by the equation \(E = \frac{M.A.}{V.R}\) x 100%.
(ii) The efficiency of a machine is 80%. Calcuate the work done by a person using the machine to raise a load of 300 kg through a height of 4 m.[ g = 10 ms\(^{-2}\) ]
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Correct Answer: Option n
Explanation:
(a)(i) Laws of solid friction states that:
— friction opposes motion
— friction depends on the nature of e surfaces
— friction is independent of the area of the surfaces in contact
— frictional force F is proportional to the normal reaction R
— friction is dependent of relative velocity between the surfaces.
ii) Advantages of friction:
— it prevents man from ipping when walking
— it provides gripping effect of beIts in machines
— for grinding when using grinding ones
— used for the production of electric charges used in the brake systems of vehicles etc.
iii) Methods of reducing friction:
— by lubrication by streamlining
— by smoothing
— by using ball bearings or rollers.
b)
(c)(i) Efficiency = \(\frac{\text{Work output}}{\text{work output}}\) x 100%
= \(\frac{\text{load x distance by load}}{\text{effort x distance moved by effort}}\)
= M.A x \(\frac{1}{VR} \times \frac{100 %}{1}\)
(ii) \(e = \frac{\text{Work output}}{\text{Work input}}\) x 100
Work input = \(\frac{\text{Work output}}{E}\) x 100
= \(\frac{300 \times 10 \times 4 \times 100}{80}\)
= 15,000J or 15KJ
(a)(i) Laws of solid friction states that:
— friction opposes motion
— friction depends on the nature of e surfaces
— friction is independent of the area of the surfaces in contact
— frictional force F is proportional to the normal reaction R
— friction is dependent of relative velocity between the surfaces.
ii) Advantages of friction:
— it prevents man from ipping when walking
— it provides gripping effect of beIts in machines
— for grinding when using grinding ones
— used for the production of electric charges used in the brake systems of vehicles etc.
iii) Methods of reducing friction:
— by lubrication by streamlining
— by smoothing
— by using ball bearings or rollers.
b)
(c)(i) Efficiency = \(\frac{\text{Work output}}{\text{work output}}\) x 100%
= \(\frac{\text{load x distance by load}}{\text{effort x distance moved by effort}}\)
= M.A x \(\frac{1}{VR} \times \frac{100 %}{1}\)
(ii) \(e = \frac{\text{Work output}}{\text{Work input}}\) x 100
Work input = \(\frac{\text{Work output}}{E}\) x 100
= \(\frac{300 \times 10 \times 4 \times 100}{80}\)
= 15,000J or 15KJ