A liquid of volume 2.00 m3 and density 1.00 x 103 is mixed with 3.00 m3 of another liquid of density 8.00 x 103kg m-3. Calculate the density of the mixture [Assuming there is no chemical reaction]
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Correct Answer: Option D
Explanation:
\(V_T = 5m^3, m_1 = 2 \times 1 \times 10^3 = 2 \times 10^3\)
\(M_2 = 3 \times 8 \times 10^3 = 24 \times 10^3\)
MT = 26 x 103
D = \(\frac{m}{v} = \frac{26 \times 10^3}{5} = 5.2 \times 10^3\)
\(V_T = 5m^3, m_1 = 2 \times 1 \times 10^3 = 2 \times 10^3\)
\(M_2 = 3 \times 8 \times 10^3 = 24 \times 10^3\)
MT = 26 x 103
D = \(\frac{m}{v} = \frac{26 \times 10^3}{5} = 5.2 \times 10^3\)