A body accelerates uniformly from rest at 2ms-2. Calculate the magnitude of its velocity after travelling 9m
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Correct Answer: Option B
Explanation:
v = \(\sqrt{U^2} + 2as = \sqrt{0^2} + 2 \times 2 \times 9 = 6\)m/s
v = \(\sqrt{U^2} + 2as = \sqrt{0^2} + 2 \times 2 \times 9 = 6\)m/s