The ice and steam point on a mercury-in-glass thermometer are 10cm and 30cm respectively. Calculate the temperature in decree Celsius when the mercury meniscus is the 14cm mark
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Correct Answer: Option A
Explanation:
\(\frac{x - 0}{100 - 0} = \frac{14 - 10}{30 - 10}\)
x = \(\frac{100 \times 4}{20} = 20^oC\)
\(\frac{x - 0}{100 - 0} = \frac{14 - 10}{30 - 10}\)
x = \(\frac{100 \times 4}{20} = 20^oC\)