Copper of thickness d is plated on the cathode of a copper voltameter. If the total surface area of the cathode is 60 cm\(^2\) and a steady current of 5.0 A is maintained in the voltameter for 1 hour. calculate the value of d. [density of copper = 8.9 x 10\(^3\)kg m\(^{-3}\) electro chemical equivalent of copper = 3.3 x 10\(^{-7}\) kg C\(^{-1}\)
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Correct Answer: Option n
Explanation:
Mass of Cu deposited = Area x thickness x density = electrochemical equivalent x current x time.
Thickness = \(\frac{\text{electrochemical equivalent} \times \text{current} \times \text{time}}{Area \times density}\)
= \(\frac{3.3 \times 10^{-7} \times 5 \times 3600}{60 \times 10^{-4} \times 8.9 \times 10^{3}}\)
= 1.1 x 10\(^{-4}\) m
Mass of Cu deposited = Area x thickness x density = electrochemical equivalent x current x time.
Thickness = \(\frac{\text{electrochemical equivalent} \times \text{current} \times \text{time}}{Area \times density}\)
= \(\frac{3.3 \times 10^{-7} \times 5 \times 3600}{60 \times 10^{-4} \times 8.9 \times 10^{3}}\)
= 1.1 x 10\(^{-4}\) m