A stone projected horizontally from the top of a tower with a speed of 4 ms\(^{-1}\) lands on the level ground at a horizontal distance 25 m from the foot of the tower. Calculate the height of the tower. g = 10 ms\(^{-2}\)]
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Correct Answer: Option n
Explanation:
Range R = U\(\sqrt{\frac{2H}{g}}\)
H = \(\frac{gR^2}{2u^2} = \frac{10 \times 25^2}{2 \times 4^2}\)
= 195.3m
Range R = U\(\sqrt{\frac{2H}{g}}\)
H = \(\frac{gR^2}{2u^2} = \frac{10 \times 25^2}{2 \times 4^2}\)
= 195.3m