An object of mass 2kg moving with a velocity 3ms-11 collides head-on with another object of mass 1kg moving in the opposite direction with a velocity of 4ms-1. If the objects stick together after collision, calculate their common speed.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
\(M_1V_1 - (M_2V_2) = V(M_1 + M_2)\)
2 x 3 - 1 x 4 = V(2 + 1)
V = \(\frac{2}{3}\)
= 0.67ms-1
\(M_1V_1 - (M_2V_2) = V(M_1 + M_2)\)
2 x 3 - 1 x 4 = V(2 + 1)
V = \(\frac{2}{3}\)
= 0.67ms-1