An object of mass 0.25kg moves at a height h above the ground with a speed of 4ms-1, if its mechanical energy at this height is 12 J, determine the value of h. [g = 10ms-1]
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Correct Answer: Option C
Explanation:
h = \(\frac{PE}{mg} - \frac{12}{0.25 \times 10} = 4.8m\)
h = \(\frac{PE}{mg} - \frac{12}{0.25 \times 10} = 4.8m\)