A direct current of 5A flow through a 0.2H inductor. Calculate the energy stored in the inductor
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Correct Answer: Option C
Explanation:
P = \(\frac{1}{2} I^2 L\)
= 5\(^2 \times\) 0.2 \(\times\) \(\frac{1}{2}\)
= 2.5J
P = \(\frac{1}{2} I^2 L\)
= 5\(^2 \times\) 0.2 \(\times\) \(\frac{1}{2}\)
= 2.5J