In a hydraulic press, a force of 40N is applied to the smaller priston of area 10cm2. If the area of the larger piston is 200cm2, calculate the force obtained
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Correct Answer: Option A
Explanation:
\(F_2 = \frac{F_1 \times A_2}{A_1} = \frac{40 \times 200}{10} = 800N\)
\(F_2 = \frac{F_1 \times A_2}{A_1} = \frac{40 \times 200}{10} = 800N\)