An ammeter connected to an a.c circuit records 5.5. The peak current in the circuit is
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Correct Answer: Option A
Explanation:
\(I_o = I_{rms} \times \sqrt{2} = 5.5 \times 1.41 = 7.8A\)
\(I_o = I_{rms} \times \sqrt{2} = 5.5 \times 1.41 = 7.8A\)