(a) State Faraday’s second law of electrolysis.
(b) An electric charge of 9.6 x 10\(^4\) C liberates 1 mole of substance containing 6.0 x 10\(^{23}\) atoms. Determine the value of the electronic charge
(b) An electric charge of 9.6 x 10\(^4\) C liberates 1 mole of substance containing 6.0 x 10\(^{23}\) atoms. Determine the value of the electronic charge
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Correct Answer: Option n
Explanation:
(a) If the same quantity of electricity is passed through different voltameters/electrolytes connected in series the masses of the substances liberated/deposited during electrolysis is (directly) proportional to their chemical equivalents.
OR The mass of an element deposited/liberated during electrolysis is (directly) proportional to the chemical equivalent of the element.
(b) Let e represent the electronic charge.
e = Faraday’s constant
Avogadro’s number
= 9.6 x 10\(^4\)
6. 0. x 10\(^{23}\)
= 1.60 x 10\(^{-19}\)C
(a) If the same quantity of electricity is passed through different voltameters/electrolytes connected in series the masses of the substances liberated/deposited during electrolysis is (directly) proportional to their chemical equivalents.
OR The mass of an element deposited/liberated during electrolysis is (directly) proportional to the chemical equivalent of the element.
(b) Let e represent the electronic charge.
e = Faraday’s constant
Avogadro’s number
= 9.6 x 10\(^4\)
6. 0. x 10\(^{23}\)
= 1.60 x 10\(^{-19}\)C