simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation
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Correct Answer: Option B
Explanation:
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)
V = WX = \(\frac{2\pi \times 0.25}{0.02} = 25\pi\)