An electric drill rated 400W is used to drill a hole in copper of mass 400g in 20s. Calculate the rise in temperature if all the heat produced is absorbed by the copper. [specific heat capacity of copper = 400Jkg-1K-1]
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Correct Answer: Option C
Explanation:
\(\theta = \frac{Pt}{MC} = \frac{400 \times 20}{0.4 \times 400} = 50^o\)
\(\theta = \frac{Pt}{MC} = \frac{400 \times 20}{0.4 \times 400} = 50^o\)